MCQ Class 10 Constructions Set II

Advertisement

1. There will be total 20  MCQ in this test.
2. Please keep a pen and paper ready for rough work but keep your books away.
3. The test will consist of only objective type multiple choice questions requiring students to mouse-click their correct choice of the options against the related question number.
4. No negative marking for incorrect choice.
5. Please click on “Finish the Test” when you want to exit.
6. All the best – Happy Studying

 

1. In the figure, AE is the bisector of exterior angle CAD meeting BC produced in E.
If AB = 10 cm, AC = 6 cm and BC = 12 cm, then CE is equal to

1

Question 1 of 20

2. In drawing triangle ABC, it is given that AB = 3 cm, BC = 2 cm and AC = 6 cm. It is not possible to draw the triangle as:

Question 2 of 20

3. D and E are the points on the sides AB and AC respectively of a triangle ABC.
If AD = 5.7, DB = 9.5 cm, AE = 4.8 cm and EC = 8 cm, then

10

Question 3 of 20

4. In the triangles PQR and NLM, angle M will be

Question 4 of 20

5. In the figure, P divides AB internally in the ratio:

1.

Question 5 of 20

6. In which of the following is AD not the bisector of angle A?

20

Question 6 of 20

7. In the figure ΔAB'C' has been constructed similar to the given ΔABC
The scale factor in this is

1

Question 7 of 20

8. If triangles PQR and DEF are similar, then which of the similarity criterion is true

2

Question 8 of 20

9. In triangle ABC, AD is the bisector of angle A, meeting BC at D, if BD = 2.5 cm, AB = 5cm and AC = 4.2 cm then DC is

1

Question 9 of 20

10. In the figure, DE is parallel to BC such that AE = one fourth of AC. If AB = 6cm, then AD is

2

Question 10 of 20

11. A point O is at a distance of 10 cm from the centre of a circle of radius 6 cm. How many tangents can be drawn from point O to the circle?

Question 11 of 20

12. If TP and TQ are two tangents to a circle with centre O so that angle POQ = 110o then angle PTQ is equal to

3

Question 12 of 20

13. In drawing triangle ABC, it is given that AB = 3 cm, BC = 2 cm and AC = 6 cm. It is not possible to draw the triangle as:

Question 13 of 20

14. A line segment AB can be divided into ratio 129 by locating a point C which divides AB in the ratio.

Question 14 of 20

15. To draw a pair of tangents to a circle which are inclined to each other at an angle of 45° it is required to draw tangents at the end point of those two radii of the circle, the angle between which is :

Question 15 of 20

16. ABCD is a quadrilateral with BC = 8 cm. Quadrilateral AB'C'D' is constructed with a scale factor 3/4 . What will be the length of B'C'?

Question 16 of 20

17. Identify the incorrect statement.

Question 17 of 20

18. Given a triangle with side AB = 8 cm. To get a line segment AB' = 3/4 of AB, it is required to divide the line segment AB in the ratio:

Question 18 of 20

19. The figure given below have been constructed by following the steps given below.
I : Draw line segment AB of length 16.9 cm and draw a ray AX making an acute angle with line segment AB.
II : Mark points A1 , A2 , A3 , A4 ........... A13 , on AX such that AA1 , = A1A2 = A2A3 and so on.
III : Join BA13 . Through the point A5 , draw a line parallel to BA13 , intersecting AB at point C.

29863_swt12

Question 19 of 20

20. AB is divided into 3 equal parts at P and Q. If AB = x AQ, then x =

Question 20 of 20

Leave a Reply

Your email address will not be published. Required fields are marked *

Advertisement