Class 10,Mathematics, Introduction to Trigonometry (Complementary Angles of Trigonometry)

1. There will be total 20 MCQ in this test.
2. Please keep a pen and paper ready for rough work but keep your books away.
3. The test will consist of only objective type multiple choice questions requiring students to mouse-click their correct choice of the options against the related question number.
4. No negative marking for incorrect choice.
5. Please click on “Finish the Test” when you want to exit.
6. All the best – Happy Studying

1. If tan 2A = cot (A – 18°), then the value of A is

 24°

 18°

  27°

 36°

Question 1 of 20

2. The value of cos² 17° – sin² 73° is

 0

 1

 -1

 3

Question 2 of 20

3. If sec 4A = cosec (A-20°),where 4A is an acute angle , find the value of A

 12°

 22°

 62°

 82°

Question 3 of 20

4. =

 

 2cot²(90°-A)

 2cosec²(90°-A)

  2tan²(90°-A)

 2sec²(90°-A)

Question 4 of 20

5. The value of cos θ cos(90° -θ) – sin θ sin (90° -θ) is:

 1

 0

 -1

 2

Question 5 of 20

6.  

 A

 B

 C

 D

Question 6 of 20

7. If (2 ^θ + 45⁰) and (30⁰ – ^θ) are acute angles, the degree measure of ^θ satisfying

sin(2^θ + 45⁰) = cos (30⁰ –^θ ) is

 15°

 80°

  30°

 20°

Question 7 of 20

8. The value of is

 2

 0

 4

 -2

Question 8 of 20

9. If cos (40° + A) = sin 30°, the value of A is:

 60°

 20°

 40°

 30°

Question 9 of 20

10.

  2cosec²(90°-A)

 2sec²(90°-A)

 2cot²(90°-A)

 2tan²(90°-A)

Question 10 of 20

11. The value of is

  2

 3

 0

 1

Question 11 of 20

12. sin (60° + θ) – cos (30° – θ) is equal to (where (60° + θ) and (30° -θ ) are both acute angles):

 0

 2 cos θ

 1

 2 sin θ

Question 12 of 20

13.

 0

 2

 1/2

 1

Question 13 of 20

14. The value of tan1°.tan2°.tan3°………. tan89° is :

 2

 1

 1/2

 0

Question 14 of 20

15. Using the ratio of complementary angles, the value of is

 2

 3

 1

 0

Question 15 of 20

16. If x sin (90° – θ) cot (90°- θ) = cos (90° – θ) then x is

 0

  -1

 2

 1

Question 16 of 20

17. If A and B are the angles of a right angled triangle ABC, right angled at C, then 1+cot²A =

  cot²B

 sec²B

  cos²B

 tan²B

Question 17 of 20

18. If tan 2A = cot (A – 18°), then the value of A is

  36°

 27°

 18°

 24°

Question 18 of 20

19. If cos = 0, then sin  can be reduced to:

  cos 2β

 sin α

  sin 2α

  cos β

Question 19 of 20

20.

 2

 3

 1

 zero

Question 20 of 20

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