Nomenclature of Co-ordination Compounds, Class 12 Chemistry NCERT Solutions

1. There will be total 10 MCQ in this test.
2. Please keep a pen and paper ready for rough work but keep your books away.
3. The test will consist of only objective type multiple choice questions requiring students to mouse-click their correct choice of the options against the related question number.
4. No negative marking for incorrect choice.
5. Please click on “Finish the Test” when you want to exit.
6. All the best – Happy Studying.

1. The hybridization of metal ion orbitals for ligand bonds in [Mn(CN)₆]^3- is:

d₂sp₃

sp₂

sp₃d₂

sp₃

Your comments:

Question 1 of 10

2. Ferrocyanide ion is a type of

Square planar complex

Octahedral complex

Tetrahedral complex

Octahedral square planar complex

Your comments:

Question 2 of 10

3. The number of unpaired electrons in [V(H2O)₆]³⁺ is:

1

4

3

2

Your comments:

Question 3 of 10

4. Valence bond theory was proposed by

Mendeleev's

Pauling

Rutherford

Werner

Your comments:

Question 4 of 10

5. Which of the following statements is not correct as per the nomenclature of coordination compounds is concerned?

The name of neutral ligands is written as such except few like aqua for water.

The oxidation state of a metal in the coordination sphere should be written in roman numerals.

The name of the anionic part should be written first.

The name of the cationic part should be written first.

Your comments:

Question 5 of 10

6. Metal posses two types of valency- Primary (ionizable) and secondary (non-ionizable) is the postulate of

Werner

Mendeleves

Rutherford

Pauling

Your comments:

Question 6 of 10

7. Metal-ligand bond arises by the donation of pairs of electrons by ligands to the metal is an assumption of

Molecular orbital theory

VSEPR theory

Valence bond theory

Crystal field theory

Your comments:

Question 7 of 10

8. Among the following which one has the highest paramagnetism?

[Zn(H₂O)₆]²⁺

[Fe(H₂O)₆]²⁺

[Cu(H₂O)₆]²⁺

[Cr(H₂O)₆]³⁺

Your comments:

Question 8 of 10

9. The complex, [Ni(CN)₄]^2-, has:

Octahedral structure

Linear structure

Tetrahedral structure

Square planar Structure

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Question 9 of 10

10. [Ni(CN)₄]^2- is a type of square planar complex where the oxidation state of Ni is:

+2

+1

+4

+3

Your comments:

Question 10 of 10

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