Chapter 10: Sound Waves — Characteristics and Applications
15 Short Answer Questions + 10 Long Answer Questions | Theory & Application Both
5 Marks LAQs
Numericals Included
CBSE/NCERT Pattern
Echo & SONAR
Wave Properties
How to Use This Q&A Sheet
- All questions are strictly from Chapter 10: Sound Waves — Characteristics and Applications.
- Short Answer Questions (SAQs) carry 2–3 marks. Write answers in 3–5 clear sentences.
- Long Answer Questions (LAQs) carry 5 marks. Always show all steps in numerical solutions.
- Questions are labelled [Theoretical] or [Practical/Application] so you know what style of answer to write.
- Bold terms are key words — always include them in your answers to score full marks.
For numericals, write the formula first → substitute values → show calculation → state the final answer with correct unit. This earns you marks even if you make a small arithmetic error.
Short Answer Questions — 15 Questions
🔊 Production & Propagation of Sound (Q1–Q5)
“Longitudinal” = parallel vibration. “Transverse” = perpendicular vibration. Always state this clearly in your answer.
📐 Wave Characteristics (Q6–Q10)
- Wavelength (λ): The distance between two consecutive crests or two consecutive troughs of a wave. SI unit: metre (m).
- Frequency (ν): The number of density oscillations at a fixed point per unit time. SI unit: hertz (Hz) or s⁻¹.
- Time Period (T): The time taken for one complete density oscillation at a fixed point. SI unit: second (s).
The relationship between time period and frequency is: ν = 1/T. A shorter time period means a higher frequency.
Frequency (ν) = Number of oscillations ÷ Time taken
ν = 15 ÷ 3
∴ Frequency = 5 Hz
Time Period (T) = 1 ÷ ν = 1 ÷ 5
∴ Time Period = 0.2 s
Formula: v = λ × ν
∴ Wavelength: λ = v ÷ ν
λ = 344 ÷ 860
∴ Wavelength (λ) = 0.4 m
🔁 Reflection, Echo & Applications (Q11–Q15)
- The time gap between the original sound and the reflected sound must be at least 0.1 second.
- The reflecting surface must be at a minimum distance of 17 m from the source (at a speed of sound of 340 m s⁻¹).
- The reflecting surface should be hard and smooth — soft or rough surfaces absorb or scatter the sound.
Total distance = v × t = 340 × 0.4 = 136 m
Distance to wall = Total distance ÷ 2
= 136 ÷ 2
∴ Distance of wall = 68 m
🏔️ Echo
- A single, distinct reflected sound heard separately from the original
- Time gap between original and reflected sound is ≥ 0.1 s
- Requires a large distance from the reflecting surface (≥ 17 m)
- Commonly heard near mountains, cliffs, or long corridors
🏛️ Reverberation
- Sound persists after source stops due to multiple reflections
- Reflections arrive with time difference < 0.05 s — brain cannot separate them
- Occurs in large closed halls or auditoriums
- Controlled using sound-absorbing panels, curtains, upholstered seats
- Infrasonic waves: Sound waves with frequency below 20 Hz. Humans cannot hear them. Animals that can detect infrasound: elephants and whales.
- Ultrasonic waves: Sound waves with frequency above 20 kHz. Humans cannot hear them. Animals that can detect ultrasound: bats, dogs, cats, and dolphins.
Total distance = v × t = 1500 × 4 = 6000 m
Depth = Total distance ÷ 2
= 6000 ÷ 2
∴ Depth of ocean = 3000 m
Long Answer Questions — 10 Questions
🔊 Sound: Production, Propagation & Waves (Q1–Q4)
- Setup: An electric bell is placed inside a sealed glass bell jar. The bell jar is connected to a vacuum pump. The bell is switched on and its sound is clearly heard through the glass jar.
- Pumping out air: As the vacuum pump slowly removes the air from inside the bell jar, the sound of the ringing bell becomes gradually fainter and fainter, even though the bell can still be seen ringing.
- Near-vacuum state: When most of the air has been removed (near-vacuum is created), almost no sound can be heard, even though the bell continues to ring visibly.
- Restoring air: When air is allowed back into the bell jar, the sound gradually returns to its original loudness.
- Conclusion: This experiment shows that sound cannot propagate in vacuum. Sound needs a material medium (solid, liquid, or gas) to travel. Such waves are called mechanical waves.
- Application to outer space: Outer space is a near-vacuum. Therefore, astronauts doing spacewalks cannot hear each other speak or hear sounds like metal objects clanking. They must use special electronic communication devices fitted in their spacesuits.
Sound is a mechanical wave — it always needs a material medium. Light, however, can travel through vacuum (it is an electromagnetic wave, not a mechanical wave).
- Average state (piston at rest): The air inside the tube has a uniform, average density. The particles are distributed evenly.
- Piston moves forward: The piston pushes the nearby air particles forward, compressing them. This creates a region of higher density called a compression (C). This compression then travels forward as the compressed particles collide with the next set of particles.
- Piston moves backward: The piston pulls back, and the air near the piston becomes less dense. This creates a region of lower density called a rarefaction (R). This rarefaction also travels forward through collisions between particles.
- Oscillating piston: As the piston oscillates repeatedly, it creates a series of alternating compressions and rarefactions that travel through the air away from the source.
- Key note: The particles of the medium do not travel with the wave — they only oscillate about their mean positions. Only the disturbance (the density variation) travels forward.
- Definitions:
- Compression: A region where air density is higher than average.
- Rarefaction: A region where air density is lower than average.
- Sound wave: The disturbance consisting of a series of alternating compressions and rarefactions propagating through a medium.
Many students write that air particles “travel” with the sound wave. This is WRONG. Only the disturbance (compression/rarefaction) travels forward. The particles themselves only vibrate about their fixed mean positions.
Part (i): For lowest frequency ν = 20 Hz
λ = v ÷ ν = 344 ÷ 20
∴ Wavelength at 20 Hz = 17.2 m
Part (ii): For highest frequency ν = 20,000 Hz
λ = v ÷ ν = 344 ÷ 20000
= 0.0172 m
∴ Wavelength at 20,000 Hz = 1.72 cm
Conclusion: The audible range of wavelengths in air spans from 1.72 cm (for high-pitched sounds) to 17.2 m (for very low-pitched sounds). This shows that lower frequency sounds have much longer wavelengths, and higher frequency sounds have shorter wavelengths. The speed of sound in a given medium remains constant — it is only the wavelength that changes when frequency changes.
20 kHz = 20,000 Hz. Always convert kHz to Hz before using in the formula. Also remember: in a given medium, speed is constant — only wavelength changes with frequency.
Distance to lightning strike:
Distance = v × t = 340 × 6
∴ Distance = 2040 m = 2.04 km
Explanation — Why lightning is seen before thunder is heard:
- Lightning (a flash of light) and thunder (a sound) are produced at the same time and place during a storm.
- Light travels at an extremely high speed of approximately 3 × 10⁸ m s⁻¹. Over a distance of 2 km, light takes less than 0.000007 seconds — practically instantaneous.
- Sound, however, travels much more slowly, at about 340 m s⁻¹. Over 2 km, it takes about 6 seconds to reach us.
- Because light arrives almost instantly while sound takes several seconds, we see the lightning first and then hear the thunder seconds later.
- The further away the lightning, the greater the time gap between seeing the flash and hearing the thunder.
You can estimate how far away a storm is by counting the seconds between the lightning flash and the thunder, then multiplying by 340 m. For example, 3 seconds → approximately 1 km away.
🔁 Echo, SONAR & Applications (Q5–Q7)
- Reflection of sound: Sound waves bounce off obstacles such as solids or liquids. This bouncing back of sound is called the reflection of sound. Sound follows the same laws of reflection as light — the angle of incidence equals the angle of reflection, with all three (incident direction, reflected direction, and normal) lying in the same plane.
- Echo: When sound reflects off a hard, smooth, and distant surface (such as a mountain, cliff, or a long corridor), and the reflected sound reaches the listener at least 0.1 second after the original sound, it is heard as a separate sound called an echo. Example: Shouting near a mountain or in a long empty corridor. The minimum distance of the reflecting surface must be 17 m (at speed = 340 m s⁻¹).
- Reverberation: In a large hall or auditorium, sound can undergo multiple reflections from the walls, ceiling, and floor. If the reflected sounds reach the listener with a time gap of less than 0.05 s, the brain cannot distinguish between them. The sound then appears to persist even after the source stops — this is called reverberation. Example: Singing in a large bathroom or speaking in an empty hall causes a prolonged “ringing” effect.
- Controlling reverberation in auditoriums: Excessive reverberation causes garbled or unclear sound. To control it, auditoriums use: sound-absorbing panels on walls and ceilings, upholstered chairs, heavy curtains, carpets, and other soft, porous materials that absorb rather than reflect sound.
The Whispering Gallery of the Gol Gumbaz in Bijapur, Karnataka, is a remarkable example of architectural acoustic design. Even a faint whisper can be heard multiple times across the large dome — an example of the clever use of sound reflection by medieval architects.
Time taken to reach the object = t ÷ 2 = 0.9 ÷ 2 = 0.45 s
Distance = v × t₁ = 1530 × 0.45
∴ Distance of underwater object = 688.5 m
Principle of SONAR:
- SONAR stands for Sound Navigation And Ranging. It uses the principle of reflection of sound (echolocation).
- A device called a transducer on a ship emits ultrasonic waves (high frequency, above 20 kHz) into the water.
- These waves travel through the water and strike underwater objects (submarines, shipwrecks, ocean floor, schools of fish) and reflect back to the ship.
- The ship receives the reflected waves (echoes) and the time taken for the echo to return is measured.
- Using the formula distance = (v × t) ÷ 2, the distance, direction, and speed of the underwater object are calculated.
In ALL echo/SONAR problems: divide total time by 2 first (to get one-way travel time), THEN multiply by speed. This is the most common error students make.
- Echolocation: The ability to locate objects by emitting sound waves and detecting the reflected echoes is called echolocation. It is essentially a natural form of SONAR used by animals.
- How bats use echolocation: Bats are nocturnal creatures (active at night) and hunt in complete darkness. Their eyes are not well-suited to navigate in the dark.
- Bats emit short bursts of ultrasonic waves (with frequencies well above 20 kHz) from their mouths or noses as they fly.
- These ultrasonic waves travel outward and reflect off nearby objects — including obstacles, trees, walls, and prey like insects.
- The reflected echoes return to the bat’s large, sensitive ears. The bat’s brain analyses these echoes to determine the position, distance, size, and movement of objects around it.
- This allows bats to avoid collisions and accurately capture prey even in complete darkness, with remarkable precision.
Other animals that use echolocation: Dolphins and whales use echolocation for navigation and hunting underwater. Some birds also use a form of echolocation.
Bats can detect prey as small as a mosquito using echolocation! They can even distinguish between different species of insects based on the echoes, and catch them mid-flight at speeds up to 50 km/h.
🎵 Human Perception & Wave Properties (Q8–Q10)
- Pitch: Pitch is how frequency is perceived by humans. A sound with a high frequency is perceived as having a high pitch (shrill sounds like a whistle or a siren). A sound with a low frequency is perceived as having a low pitch (deep sounds like thunder or an aircraft rumble). The higher the frequency, the higher the pitch.
- Loudness: Loudness is how amplitude is perceived by humans. Sounds with larger amplitude are perceived as louder; sounds with smaller amplitude are perceived as softer. Loudness depends not just on amplitude but also on the hearing ability of the listener. It decreases as we move farther from the source because sound spreads over a larger area.
- Intensity: Intensity is a measurable physical quantity — it is the amount of sound energy passing through a unit area perpendicular to the direction of propagation per unit time. It is not the same as loudness. Loudness is the subjective perception, while intensity is objective and can be measured (in decibels, dB).
- Decibel scale: Normal conversation ≈ 60 dB. Firecrackers can exceed 100 dB. Rustling leaves are around a few dB. Prolonged exposure to high dB sounds can cause permanent hearing loss.
Pitch ↔ Frequency (objective) | Loudness ↔ Amplitude + listener ability (subjective) | Intensity ↔ Energy per unit area per unit time (objective, measurable in dB)
Part (i) — Frequency (ν):
Formula: v = λ × ν
∴ ν = v ÷ λ = 5000 ÷ 50
∴ Frequency (ν) = 100 Hz
Part (ii) — Time Period (T):
Formula: T = 1 ÷ ν
T = 1 ÷ 100
∴ Time Period (T) = 0.01 s
Verification: We can verify: v = λ × ν = 50 × 100 = 5000 m s⁻¹ ✓
Always verify your answer by substituting back into the formula. This takes 5 seconds and can earn you the verification mark if the examiner looks for it.
Four Applications of Ultrasonic Waves:
- Medical imaging (Ultrasonography): Used for imaging internal organs such as the kidney, liver, and foetus without surgery.
- Breaking kidney stones: High-intensity ultrasonic waves break kidney stones into smaller pieces that can then be passed out of the body naturally.
- Industrial cleaning: Used for cleaning delicate machine parts, jewellery, and electronic components in industries.
- Detecting defects in metals: Ultrasonic waves are used to detect cracks or defects inside metal blocks during construction and industrial testing (non-destructive testing).
- SONAR: Used for detecting and locating underwater objects (submarines, shipwrecks, ocean floor depth).
Verification of parking sensor:
Total distance = 2 × 1.2 = 2.4 m
Time = Total distance ÷ v = 2.4 ÷ 345
= 0.00696 s ≈ 0.007 s
∴ Verified: Echo returns in ≈ 0.007 s ✓
Formula & Key Terms Quick Reference
| Key Term | Definition | Physical Property |
|---|---|---|
| Compression | Region of higher-than-average density in medium | Crest on density-distance graph |
| Rarefaction | Region of lower-than-average density in medium | Trough on density-distance graph |
| Wavelength (λ) | Distance between two consecutive crests or troughs | SI unit: metre (m) |
| Frequency (ν) | Number of oscillations per unit time at a point | SI unit: Hz (hertz) |
| Amplitude | Maximum change in density from average | Related to loudness and energy |
| Pitch | Human perception of frequency | High freq = high pitch |
| Loudness | Human perception of amplitude | Large amplitude = louder |
| Infrasound | Sound below 20 Hz | Detected by elephants, whales |
| Ultrasound | Sound above 20 kHz | Detected by bats, dogs, dolphins |
| Echo | Reflected sound heard after ≥ 0.1 s | Min distance: 17 m |
| Reverberation | Multiple reflections making sound persist | Time gap < 0.05 s |
| SONAR | Sound Navigation And Ranging | Uses ultrasound + echolocation |
Common Exam Mistakes to Avoid
The total time given is always the time for sound to travel TO the obstacle AND BACK. Always divide the total time by 2 before multiplying by speed to get the one-way distance.
Particles of the medium do NOT travel with the sound wave. They only vibrate/oscillate about their mean positions. Only the disturbance (compression/rarefaction) travels forward.
Echo = time gap ≥ 0.1 s between original and reflected sound (heard as separate). Reverberation = time gap < 0.05 s, multiple reflections, sound seems to persist. Never mix these up.
Intensity is an objective, measurable physical quantity (energy per unit area per unit time). Loudness is the subjective perception of amplitude — it also depends on the individual listener’s hearing ability.
Remember: Sound travels FASTEST in solids, SLOWER in liquids, SLOWEST in gases. Steel (5000 m s⁻¹) > Water (1500 m s⁻¹) > Air (340 m s⁻¹). Never say sound travels fastest in air.
1 kHz = 1000 Hz. So 20 kHz = 20,000 Hz. Always convert before using in formulas. Failing to convert gives an answer that is 1000 times wrong.
Sound CANNOT travel in vacuum. In movies, spacecraft explosions are shown with sound — this is scientifically incorrect. Sound is a mechanical wave and always needs a material medium.
Quick Revision Summary
Production of Sound
Sound is produced by vibrating objects. Vocal cords in humans, strings in instruments, and air columns in flutes all produce sound through vibration.
Sound Wave
A longitudinal mechanical wave — series of alternating compressions (C) and rarefactions (R). Particles oscillate parallel to direction of propagation. Needs a medium.
Wave Properties
Wavelength (λ): distance between two crests. Frequency (ν): oscillations per second (Hz). Time period (T): time for one oscillation. ν = 1/T.
Wave Speed Formula
v = λ × ν. Speed depends on medium: fastest in solids, slowest in gases. In air: ≈ 340 m s⁻¹. Speed increases with temperature and humidity.
Echo & Reverberation
Echo: reflected sound heard after ≥ 0.1 s (min distance 17 m). Reverberation: multiple reflections in closed space, time gap < 0.05 s, sound persists.
Echolocation & SONAR
Bats, dolphins use echolocation. SONAR = Sound Navigation and Ranging. Uses ultrasonic waves reflected off underwater objects. d = (v × t) / 2.
Pitch & Loudness
Pitch = perception of frequency (high freq = high pitch). Loudness = perception of amplitude (large amplitude = louder). Audible range: 20 Hz to 20 kHz.
Infrasound & Ultrasound
Infrasound: < 20 Hz (elephants detect it). Ultrasound: > 20 kHz (bats, dogs detect it). Applications: medical imaging, kidney stone breaking, SONAR, industrial testing.
For numericals — write the formula first, then substitute values with units, then calculate. For echo/SONAR — always divide total time by 2. For definition questions — include the key term in bold, give a clear one-sentence definition, then support with an example. Sound is a very calculation-heavy chapter — practice all the worked examples in the chapter thoroughly. All the best! 🌟

Leave a Reply