Chapter 8: Journey Inside the Atom
15 Short Answer + 10 Long Answer Questions | Theory & Application | Step-by-Step Solutions
5 Marks (LAQ)
CBSE Pattern
Numericals Included
Atomic Models
Isotopes & Isobars
How to Use This Q&A Sheet
- All questions are strictly based on Chapter 8: Journey Inside the Atom content only.
- Short Answer Questions (SAQ) carry 2–3 marks and need answers in 3–5 sentences.
- Long Answer Questions (LAQ) carry 5 marks — always write step-by-step, use sub-headings and label key terms.
- Look for the [Theoretical] or [Practical/Application] label on each question so you know what type of answer is expected.
- For numerical questions, always write: Given → Formula → Substitution → Answer with units.
First attempt all SAQs you know well, then tackle the LAQs. Always write the answer in your own words — copying the textbook line-by-line can cost you marks in application-type questions.
Short Answer Questions — 15 Questions (2–3 Marks Each)
⚗️ Chemistry Questions (Q1–Q10 — Atomic Structure Focus)
Mention the Sanskrit text “Vaisesika Sutras” for an extra mark — examiners appreciate specific names.
The charge of an electron is –1.602 × 10⁻¹⁹ C, taken as –1 by convention.
- Most of an atom is empty space, as most alpha particles passed through the gold foil without deflection.
- The nucleus is dense, positively charged, and contains most of the atom’s mass — concentrated in an extremely small region at the centre.
- Electrons revolve around the nucleus in orbits, somewhat like planets orbiting the Sun.
⚗️ Chemistry Questions Continued (Q6–Q10)
- Electrons move in fixed circular paths called stationary states, orbits, or shells around the nucleus.
- Each shell has a definite energy, so they are also called energy levels, represented as K, L, M, N (or n = 1, 2, 3, 4…).
- While moving in a fixed shell, an electron does not lose energy.
- An electron moves to another shell by absorbing or releasing a fixed amount of energy equal to the difference between the two energy levels.
Number of protons = Atomic number = 17
Number of electrons = Number of protons (neutral atom) = 17
Number of neutrons = A − Z = 35 − 17 = 18
Electronic configuration: K = 2, L = 8, M = 7
∴ Protons = 17, Electrons = 17, Neutrons = 18; Config: 2, 8, 7
This element is Chlorine (Cl).
Isotopes differ in physical properties like boiling point and melting point, but their chemical behaviour is the same.
🔬 Mixed Theory & Application Questions (Q11–Q15)
- Sodium (Na) has configuration 2, 8, 1. It loses 1 electron to attain an octet → Valency = 1.
- Oxygen (O) has configuration 2, 6. It gains 2 electrons to complete its octet → Valency = 2.
Elements with a complete octet (8 electrons in outer shell), like Neon, have valency 0 and are unreactive.
Formula: Avg mass = (mass₁ × abundance₁) + (mass₂ × abundance₂)
Substituting: = (35 × 75/100) + (37 × 25/100)
= (105/4) + (37/4)
= 142/4
∴ Average Atomic Mass of Chlorine = 35.5 u
- K-shell (n = 1): 2 × 1² = 2 electrons
- L-shell (n = 2): 2 × 2² = 8 electrons
- M-shell (n = 3): 2 × 3² = 18 electrons
Additionally, the outermost shell can hold a maximum of 8 electrons, and electrons fill shells from the innermost (K) outward.
Filling shells using 2n² rule:
K-shell: 2 electrons
L-shell: 8 electrons
M-shell: 2 electrons (remaining)
Electronic configuration: 2, 8, 2
Valence electrons in outermost shell = 2
Since fewer than 4 → Mg loses 2 electrons
∴ Electronic configuration: 2, 8, 2 | Valency of Mg = 2
Long Answer Questions — 10 Questions (5 Marks Each)
⚗️ Atomic Models & Structure (Q1–Q4)
- Dalton’s Atomic Model (1808): John Dalton proposed that all matter is composed of indivisible particles called atoms. This was the first scientific model. Limitation: It could not explain the existence of subatomic particles or the internal structure of the atom.
- Thomson’s Plum Pudding Model (1897): After discovering electrons, J.J. Thomson proposed the atom as a sphere of positive charge with electrons embedded throughout — like a watermelon. Limitation: It failed to explain the results of Rutherford’s gold foil experiment.
- Rutherford’s Planetary Model (1911): Based on the gold foil experiment, Rutherford proposed a dense, positively charged nucleus at the centre with electrons orbiting around it like planets. Limitation: Could not explain why orbiting electrons don’t lose energy and spiral into the nucleus (atomic stability).
- Bohr’s Model (1913): Niels Bohr proposed that electrons move in fixed energy levels (shells) and do not lose energy while in a fixed orbit. Electrons absorb or emit energy only when jumping between shells. This explained atomic stability.
- Modern Model: Even Bohr’s model had limitations. Today’s quantum mechanical model describes electrons as electron clouds — regions of probability around the nucleus. This is still being refined.
Ernest Rutherford was born in New Zealand and worked under J.J. Thomson at Cambridge. He is known as the “Father of Nuclear Physics” and won the Nobel Prize in Chemistry in 1908. His portrait appears on New Zealand’s $100 banknote!
- Setup: A narrow beam of alpha (α) particles (positively charged, emitted by radioactive elements) was directed at an extremely thin sheet of gold foil.
- Expected Observation (Thomson’s model): Since Thomson’s model had positive charge spread evenly, alpha particles were expected to pass straight through or be deflected only slightly.
- Actual Observation 1: Most alpha particles passed through the gold foil without any deflection.
- Actual Observation 2: Some alpha particles were deflected at large angles.
- Actual Observation 3: A very few alpha particles bounced straight back (nearly 180°).
- Conclusions:
- Most of the atom is empty space (most particles passed through).
- All the positive charge and most mass is concentrated in a tiny, dense nucleus (few particles bounced back — hitting the nucleus).
- Electrons revolve around the nucleus in the large empty space around it.
- The diameter of atom ≈ 10⁻¹⁰ m; nucleus ≈ 10⁻¹⁵ m — the nucleus is ~10⁵ times smaller than the atom.
Students often write that “most particles bounced back.” This is WRONG. Only a very few particles bounced back. MOST passed through undeflected. Always remember this distinction.
- Fixed Shells (Stationary States): Electrons revolve around the nucleus only in fixed circular paths called stationary states, orbits, or shells. These are named K, L, M, N… (or n = 1, 2, 3, 4…).
- Fixed Energy Levels: Each shell has a definite, fixed amount of energy. The K-shell (n=1) has the least energy and is closest to the nucleus. Energy increases as we move farther from the nucleus.
- No Energy Loss in Fixed Orbit: While moving in its fixed shell, an electron does not radiate energy. This explains why electrons don’t spiral into the nucleus — atomic stability is maintained.
- Energy Transition: An electron jumps to a higher shell by absorbing energy and falls to a lower shell by releasing energy. The energy absorbed/emitted is exactly equal to the difference between the two energy levels.
- Electron Capacity per Shell: Each shell can hold only a maximum number of electrons (given by 2n²).
- Limitation of Bohr’s Model: Bohr’s model was later found to be incorrect because electrons do not follow well-defined circular orbits. The modern quantum mechanical model describes them as electron clouds (regions of probability).
The naming of shells K, L, M, N… (not A, B, C) came from early X-ray experiments by Charles Barkla. Including this fact in your answer earns bonus marks.
Step 1 — Find Atomic Number (Z):
A = protons + neutrons → Z = A − n⁰ = 40 − 20 = 20
Step 2 — Find Number of Electrons:
For a neutral atom, electrons = protons = 20
Step 3 — Electronic Configuration (using 2n²):
K-shell: 2, L-shell: 8, M-shell: 8, N-shell: 2
Configuration: 2, 8, 8, 2
Step 4 — Identify the Element:
Z = 20 → This is Calcium (Ca)
Step 5 — Valency:
Outermost shell (N) has 2 electrons → Calcium tends to lose 2 electrons
∴ Atomic number = 20 | Electrons = 20 | Config = 2,8,8,2 | Element = Calcium | Valency = 2
⚗️ Discovery of Subatomic Particles & Symbols (Q5–Q7)
- Electron: Discovered by J. J. Thomson in 1897 through cathode ray tube experiments. Electrons are negatively charged particles with charge –1 (relative). They orbit the nucleus in fixed energy levels.
- Proton: Discovered and named by Rutherford. He showed that the nucleus carries positive charge from particles called protons. A proton has a relative charge of +1 and is much heavier than an electron. The number of protons = atomic number of the element.
- Neutron: Discovered by James Chadwick in 1932. Neutrons are present in the nucleus of all atoms except hydrogen. They have a mass nearly equal to a proton but carry no charge (neutral). They help explain why atomic mass is greater than what protons alone account for.
- Summary Table:
Particle Symbol Relative Charge Location Electron e⁻ –1 Orbits (shells) Proton p⁺ +1 Nucleus Neutron n⁰ 0 Nucleus - Atomic Neutrality: For an atom to be electrically neutral, the number of protons must equal the number of electrons. For example, helium has 2 protons and 2 electrons.
- Atomic Number (Z): The number of protons in the nucleus of an atom is called its atomic number, denoted by Z. Since a neutral atom has equal protons and electrons, Z also equals the number of electrons. Atomic number uniquely identifies an element — no two elements have the same atomic number. Example: Hydrogen has Z = 1 (1 proton), Helium has Z = 2 (2 protons).
- Mass Number (A): The total number of protons and neutrons (collectively called nucleons) in the nucleus is the mass number, denoted by A. Formula: A = p⁺ + n⁰. Electrons are not counted as their mass is negligible.
- Standard Notation: An atom is represented as:ᴬ_Z Element Symbol — where A is the mass number (top-left) and Z is the atomic number (bottom-left).
Example: Carbon is written as ¹²₆C (Z = 6 protons, A = 12, neutrons = 12 − 6 = 6).
- More Examples:
Element Protons (Z) Neutrons Mass Number (A) Hydrogen 1 0 1 Helium 2 2 4 Lithium 3 4 7 - Key Point: The number of neutrons = A − Z. Elements are defined by their atomic number, not their mass number.
Mass Number = Protons + Neutrons (nucleons). Electrons are NOT included in mass number because their mass is negligible.
- Part 1 — Average atomic mass of Bromine:Given: ⁷⁹Br: mass = 79 u, abundance = 49.7% | ⁸¹Br: mass = 81 u, abundance = 50.3%
Formula: Avg mass = (m₁ × a₁/100) + (m₂ × a₂/100)
= (79 × 49.7/100) + (81 × 50.3/100)
= 39.263 + 40.743
∴ Average Atomic Mass of Bromine ≈ 80 u - Part 2 — Why Chlorine’s average atomic mass is 35.5 u: Chlorine has two naturally occurring isotopes — ³⁵Cl (75%) and ³⁷Cl (25%). A simple arithmetic average ignores how commonly each isotope occurs in nature. The weighted average, which multiplies each isotope’s mass by its natural abundance, gives 35.5 u. This is not a whole number because it is a statistical average across millions of atoms — no single chlorine atom has a mass of 35.5 u; individual atoms are either 35 u or 37 u.
- Key Principle: The average atomic mass of an element is always calculated using its weighted average based on natural abundances of its isotopes — not a simple average.
🌐 Applications of Isotopes & Symbols of Elements (Q8–Q10)
- Nuclear Energy: ²³⁵₉₂U (Uranium-235) is used as fuel in nuclear reactors to generate electricity in nuclear power plants. The splitting (fission) of Uranium-235 nuclei releases enormous amounts of energy.
- Cancer Treatment: ⁶⁰₂₇Co (Cobalt-60) is a radioactive isotope used in radiation therapy for cancer patients. Its gamma rays target and destroy tumour cells.
- Thyroid Treatment: ¹³¹₅₃I (Iodine-131) is used to treat goitre and thyroid cancer. The thyroid gland absorbs iodine, allowing the radioactive isotope to treat the gland directly.
- Archaeology & Geology (Carbon Dating): ¹⁴₆C (Carbon-14) is used to determine the age of ancient fossils and artefacts. Living organisms absorb C-14 from the atmosphere; after death, C-14 decays at a known rate, allowing scientists to date the sample.
- Bhabha Atomic Research Centre (BARC): India’s BARC in Mumbai uses reactors like Dhruva for neutron scattering experiments, helping develop better medicines, energy storage, and industrial alloys.
Homi Jehangir Bhabha, known as the father of India’s nuclear programme, established BARC and TIFR. His work paved the way for India to use atomic energy for peaceful purposes including electricity generation, agriculture support, and advanced medical treatments.
• Atoms of the same element
• Same atomic number (Z)
• Different mass numbers (A)
• Same number of electrons → same chemical properties
• Different number of neutrons
Examples: ¹H, ²H, ³H (Hydrogen isotopes); ¹²C, ¹³C, ¹⁴C (Carbon isotopes)
• Atoms of different elements
• Different atomic numbers (Z)
• Same mass number (A)
• Different number of electrons → different chemical properties
• Different number of protons and neutrons
Examples: ⁴⁰Ca (Z=20), ⁴⁰K (Z=19), ⁴⁰Ar (Z=18)
- Why isotopes have similar chemical properties: Chemical properties depend primarily on the number of electrons (especially valence electrons) and the electronic configuration. Since isotopes have the same number of protons → same number of electrons → same electronic configuration, they behave the same way chemically.
- Why isobars have different chemical properties: Isobars belong to different elements with different atomic numbers → different numbers of protons and electrons → different electronic configurations → different valency and chemical behaviour. For example, Calcium (Z=20) and Argon (Z=18) have very different chemical properties despite both having mass number 40.
(i) Atomic Number (Z):
Z = A − n⁰ = 35 − 18 = 17
(ii) Electrons and Protons:
Protons = Z = 17
Electrons = Z (neutral atom) = 17
(iii) Element Identification:
Z = 17 → This is Chlorine (Cl)
(iv) Electronic Configuration:
K = 2, L = 8, M = 7 → 2, 8, 7
(v) Valency:
Outermost shell has 7 electrons → gains 1 electron to complete octet
Valency = 1
(vi) New Mass Number after adding 2 neutrons:
New A = 35 + 2 = 37
(vii) Relation:
Both atoms have Z = 17 (same element) but different mass numbers (35 and 37)
∴ The new atom (³⁷Cl) is an ISOTOPE of element X (³⁵Cl)
Adding neutrons changes the mass number but NOT the atomic number — so the element identity stays the same, making the new atom an isotope of the original.
Formula & Key Terms Quick Reference
| Term | Definition |
|---|---|
| Atomic Number (Z) | Number of protons in the nucleus; uniquely identifies an element |
| Mass Number (A) | Total number of nucleons (protons + neutrons) in the nucleus |
| Valency | Number of electrons gained, lost, or shared to complete the octet |
| Isotopes | Same element, same Z, different A (same chemical properties) |
| Isobars | Different elements, same A, different Z (different chemical properties) |
| Nucleus | Dense, positively charged centre of an atom containing protons and neutrons |
| Valence Electrons | Electrons in the outermost shell — determine chemical reactivity |
| Octet | 8 electrons in the outermost shell → stable, unreactive configuration |
Common Exam Mistakes to Avoid
Students often mix up Z (protons) and A (protons + neutrons). Remember: Z identifies the element; A tells you the total mass. Neutrons = A − Z.
Only a VERY FEW particles bounced back. MOST passed straight through. This distinction is critical and frequently tested.
Mass number = protons + neutrons ONLY. Electrons are not included because their mass is negligible.
Isotopes have the SAME chemical properties (same electrons, same configuration) but different PHYSICAL properties (melting point, boiling point). Isobars have different chemical properties.
Never add isotope masses and divide equally. Always use weighted average: multiply each mass by its % abundance, then add. Chlorine’s average is 35.5 u (not 36 u).
The formula 2n² gives the total capacity, but the OUTERMOST shell can never have more than 8 electrons (first shell maximum is 2). This is tested in electronic configuration questions.
Thomson’s model failed because it couldn’t explain the gold foil experiment results. Rutherford’s model failed because it couldn’t explain atomic stability (electrons spiralling into nucleus). Keep these separate!
⚡ Quick Revision Summary
In this chapter, the most marks come from: (1) Drawing and explaining atomic models with their limitations, (2) Numerical problems on atomic number, mass number, and electronic configuration, and (3) Distinguishing isotopes from isobars with examples. Always write answers in points for LAQs — examiners award marks per point. For numericals, always show all steps: Given → Formula → Substitution → Answer with units. Good luck! 🌟

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