Mole Concept, Class 11 Chemistry NCERT Solutions

Some Basic Concepts Of Chemistry Q – 1.22, CBSE Class 11th Chemistry

Some Basic Concepts Of Chemistry Q – 1.23, Class 11th Chemistry

Some Basic Concepts Of Chemistry Q – 1.24, Chemistry CBSE Class 11th

Some Basic Concepts Of Chemistry Q – 1.25, CBSE Class 11th Chemistry

Some Basic Concepts Of Chemistry Q – 1.26, CBSE Class 11th Chemistry

Some Basic Concepts Of Chemistry Q – 1.27, NCERT Chemistry Class 11th

Some Basic Concepts Of Chemistry – Page No 24 Ques 1.29, Class 11th CBSE Chemistry

1. There will be total 20  MCQ in this test.
2. Please keep a pen and paper ready for rough work but keep your books away.
3. The test will consist of only objective type multiple choice questions requiring students to mouse-click their correct choice of the options against the related question number.
4. No negative marking for incorrect choice.
5. Please click on “Finish the Test” when you want to exit.
6. All the best – Happy Studying.

1. Vapour density of a gas is 22. Its molecular mass will be:

  33g

 44g

 22g

 11g

Question 1 of 21

2. What is the mass of 0.20 mole of C₂H₅OH (ethanol)?

  46 g

 23 g

 4.6 g

 none of these

Question 2 of 21

3. Consider the reaction between hydrogen and oxygen gases to form water. Which of the following is/are not conserved in the reaction?
2H₂(g) + O₂(g) → 2H₂O(l)

  Atoms

 Mass

 Both moles of molecules and moles of atoms

 Moles of molecules

Question 3 of 21

4. How many moles of NaCl should be dissolved in 100 mL of water to get 0.2 M solution?

 0.2

 0.02

 0.01

 0.1

Question 4 of 21

5. Molarity of NaOH in a solution prepared by dissolving 4 g of NaOH in enough water to form 250 ml of solution is:

  1.4 M

 0.45 M

 0.4 M

 4.1 M

Question 5 of 21

6. Number of atoms present in 52 g of helium is:
(N_A is Avogadro’s constant Gram atomic mass of He is 4 g)

  26 X N_A

 N_A

 13 X N_A

 52 Χ N_A

Question 6 of 21

7. 18 g of glucose (C₆H₁₂O₆) is present in 1000 g of an aqueous solution of glucose. The molality of this solution is:

  1m

 0.1m

 1.1m

 0.5m

Question 7 of 21

8. Atomic mass of Cl is 35.5 g. Calculate the mass of 4.50 moles of chlorine gas, Cl₂.

  6.34 g

 4.5 g

 160 g

  319.5 g

Question 8 of 21

9. Atomic mass of bromine is 80 g. The mass of four moles of molecular bromine (Br₂) is:

  80 g

 40 g

  640 g

 320 g

Question 9 of 21

10. Number of nitrogen atoms present in 1.4 g of N₂:

  6.023 X 10₂₂

 6.023 X 10₂₃

 3.012 X 10₂₃

 3.012 X 10₂₂

Question 10 of 21

11. Volume of 17g of NH₃ at N.T.P. will be

  22.4 L

 2.24 L

 4.48 L

 44.8 L

Question 11 of 21

12. Mass of one atom of calcium is:

 A

 B

 C

 D

Question 12 of 21

13. Which of the following has maximum number of moles?

  1g of O₂

 1g of H₂

 1g of Cl₂

 1g of N₂

Question 13 of 21

14. Molar mass of F₂ is 38 g. How many atoms are present in 0.147 mole of F₂?

  6.02 Χ 10₂₃ atoms

 8.78 Χ 10₂₂2 atoms

 0.292 atoms

 1.76 Χ 10₂₃ atoms

Question 14 of 21

15. Molar mass of F₂ is 38 g. How many atoms are present in 0.147 mole of F₂?

  6.02 Χ 10₂₃ atoms

 8.78 Χ 10₂₂2 atoms

 0.292 atoms

 1.76 Χ 10₂₃ atoms

Question 15 of 21

16. Number of moles of hydroxide ions in 0.3L of 0.005M solution of Ba (OH)₂ is:

  0.0015

 0.003

 0.0050

 0.0075

Question 16 of 21

17. Mass of 6.022 x 10²² molecules of CO₂ is about:

  1.4 g

 2.2 g

 12 g

 4.4 g

Question 17 of 21

18. A solution is prepared by adding 2 g of a substance A to 18 g of water. Mass percent of solute A will be:

 15%

 10%

 20%

  25%

Question 18 of 21

19. Which sample contains the greatest number of nitrogen atoms? (All measurements are taken at STP.)

 0.40 mol N₂ (g)

 40 g NH₃(g)

 0.20 mol N₂O₄ (g)

 80 g N₂O₄(g)

Question 19 of 21

20. Normality is defined as:

 Number of moles of solute per litre of solution

 Number of gram equivalents of solute per litre of solution

 Amount of solute present in 100g of solution

 Number of moles of solute per 1000g of solvent

Question 20 of 21

21. Atomic mass of Si is 28 g. How many silicon atoms are there in 1.00 g of silicon?

  2.14 Χ 10₂₂ atoms

 1.75 Χ 10₂₅ atoms

 1 atom

 0.0356 atoms

Question 21 of 21

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