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Class 6th Maths || Menu
  • Important
    • Important Formulas
    • Mathematics Book
    • MCQs
    • Revision
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  • Knowing your Numbers
    • Ex 1.1
    • Ex 1.2
    • Ex 1.3
    • MCQs
    • Ex. 1.1 Solutions
    • Ex. 1.2 Solutions
    • Ex. 1.3 Solutions
    • Close
  • Whole Numbers
    • Ex 2.1
    • Ex 2.2
    • Ex 2.3
    • MCQs
    • Ex. 2.1 NCERT Solutions
    • Ex. 2.2 NCERT Solutions
    • Ex. 2.3 NCERT Solutions
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  • Playing with Numbers
    • Ex 3.1
    • Ex 3.2
    • Ex 3.3
    • Ex 3.4
    • Ex 3.5
    • Ex 3.6
    • Ex 3.7
    • MCQs
    • Ex. 3.1 NCERT Solutions
    • Ex. 3.2 NCERT Solutions
    • Ex. 3.3 NCERT Solutions
    • Ex.3.4 NCERT Solutions
    • Ex.3.5 NCERT Solutions
    • Ex.3.6 NCERT Solutions
    • Ex.3.7 NCERT Solutions
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  • Basic Geometrical Ideas
    • Ex 4.1
    • Ex 4.2
    • Ex 4.3
    • Ex 4.4
    • Ex 4.5
    • Ex 4.6
    • MCQs
    • Ex. 4.1 NCERT Solutions
    • Ex 4.2 NCERT Solutions
    • Ex. 4.3 NCERT Solutions
    • Ex. 4.4 NCERT Solutions
    • Ex. 4.5 NCERT Solutions
    • Ex. 4.6 NCERT Solutions
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  • Understanding Elementary Shapes
    • Ex 5.1
    • Ex 5.2
    • Ex 5.3
    • Ex 5.4
    • Ex 5.5
    • Ex 5.6
    • Ex 5.7
    • Ex 5.8
    • Ex 5.9
    • MCQs
    • Ex 5.1 NCERT Solutions
    • Ex 5.2 NCERT Solutions
    • Ex 5.3 NCERT Solutions
    • Ex 5.4 NCERT Solutions
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    • Ex 5.6 NCERT Solutions
    • Ex 5.7 NCERT Solutions
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  • Integer
    • Ex 6.1
    • Ex 6.2
    • Ex 6.3
    • MCQs
    • Ex 6.1 NCERT Solutions
    • Ex 6.2 NCERT Solutions
    • Ex 6.3 NCERT Solutions
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  • Fractions
    • Ex 7.1
    • Ex 7.2
    • Ex 7.3
    • Ex 7.4
    • Ex 7.5
    • Ex 7.6
    • MCQs
    • Ex 7.1 NCERT Solutions
    • Ex 7.2 NCERT Solutions
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  • Decimals
    • Ex 8.1
    • Ex 8.2
    • Ex 8.3
    • Ex 8.4
    • Ex 8.5
    • Ex 8.6
    • MCQs
    • Ex 8.1 NCERT Solutions
    • Ex 8.2 NCERT Solutions
    • Ex 8.3 NCERT Solutions
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    • Ex 8.6 NCERT Solutions
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  • Data Handling
    • Ex 9.1
    • Ex 9.2
    • Ex 9.3
    • Ex 9.4
    • MCQs
    • Ex 9.1 NCERT Solutions
    • Ex 9.2 NCERT Solutions
    • Ex 9.3 NCERT Solutions
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  • Mensuration
    • Ex 10.1
    • Ex 10.3
    • MCQs
    • Ex 10.1 NCERT Solutions
    • Ex 10.2 NCERT Solutions
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  • Algebra
    • Ex 11.1
    • Ex 11.2
    • Ex 11.3
    • Ex 11.4
    • Ex 11.5
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    • Ex 11.1 NCERT Solutions
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  • Ratio and Proportion
    • Ex 12.1
    • Ex 12.2
    • Ex 12.3
    • MCQs
    • Ex 12.1 NCERT Solutions
    • Ex 12.2 NCERT Solutions
    • Ex 12.3 NCERT Solutions
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  • Symmetry
    • Ex 13.1
    • Ex 13.2
    • MCQs
    • Ex 13.1 NCERT Solutions
    • Ex 13.2 NCERT Solutions
    • Ex 13.3 NCERT Solutions
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  • Practical Geometry
    • Ex 14.1
    • Ex 14.2
    • Ex 14.1 NCERT Solutions
    • Ex 14.2 NCERT Solutions
    • Ex 14.3 NCERT Solutions
    • Ex 14.4 NCERT Solutions
    • Ex 14.5 NCERT Solutions
    • Ex 14.6 NCERT Solutions
      • MCQs
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Class 6 Ex.14.6 Maths NCERT Solutions

NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.6

Ex 14.6 Class 6 Maths Question 1.
Draw ∠POQ of measure 75° and find its line of symmetry.

Solution:

Step I : Draw a line segment P̅Q̅ .
Step II : With centre Q and suitable radius, draw an arc to cut PQ at R.

Step III : With centre R and radius of the same length, mark S and T on the former arc.
Step IV : With centres S and T and with the same radius, draw two arcs which meet each other at U.
Step V: Join QU such that ∠PQU = 90°.
Step VI : With centres S and W, draw two arcs of the same radius which meet each other at Q.
Step VII: Join Q and O such that ∠PQO = 75°.
Step VIII: Bisect ∠PQO with QV.
Thus, OV is the line of symmetry of ∠PQO.

Ex 14.6 Class 6 Maths Question 2.
Draw an angle of measure 147° and construct its bisector.

Solution:

Step I : Draw ∠ABC = 147° with the help of protractor.

Step II : With centres B and radius of proper length, draw an arc which meets AB and AC at E and F respectively.
Step III : With centres E and F and the radius more that half of the length of arc EF, draw two arcs which meet each other at D.
Step IV : Join B and D.
Thus, BD is the bisector of ∠ABC.

Ex 14.6 Class 6 Maths Question 3.
Draw a right angle and construct its bisector.

Solution:

Step I: Draw a line segment AB.
Step II : With centre B and proper radius draw an arc to meet AB at C.

Step III : With centre C and same radius, mark two marks D and E on the former arc.
Step IV : With centres D and E and the same radius, draw two arcs which meet each other at G.
Step V : Join B and G such that ∠ABG = 90°
Step VI : Draw BH as the bisector of ∠ABG such that ∠ABH = 45°.
Thus ∠ABG is the right angle and BH is the bisector of ∠ABG.

Ex 14.6 Class 6 Maths Question 4.
Draw an angle of 153° and divide it into four equal parts.

Solution:

Step I : Draw ∠ABP = 153° with the help of protractor.

Step II : Draw BC as the bisector of ∠ABP which dividers ∠ABP into two equal parts.
Step III : Draw BD and BE as the bisector of ∠ABC and ∠CBP respectively.
Thus, the bisectors BD, BC and BE divide the ∠ABP into four equal parts.

Ex 14.6 Class 6 Maths Question 5.
Construct with ruler and compasses, angles of the following measures:
(a) 60°

(b) 30°

(c) 90°

(d) 120°

(e) 45°

(f) 135°

 

Solution:

(a) Angle of 60°

Step I: Draw a line segment A̅B̅ .
Step II : With centre B and proper radius draw an arc.
Step III : With centre D and radius of the- same length mark a point E on the former arc.
Step IV : Join B to E and product to C. Thus ∠ABC is the required angle of measure 60°.

(b) Step I: Draw ∠ABC = 60° as we have done in section (a).
Step II: Draw BF as the bisector of ∠ABC.

Thus ∠ABF = 60/2 = 30°.

(c) Angle of 90°
In the given figure,
∠ABC = 90°(Refer to solution 3)

(d) Angle of 120°.
Step I: Draw A̅B̅
Step II : With centre A and radius of proper length, draw an arc.

Step III : With centre D and the same radius, draw two mark E and F on former arc.
Step IV : Join A to F and produce to C. Thus ∠CAB = 120°

(e) Angle of 45s, i.e., 90/2 = 45°
In the figure ∠ABD = 45° (Refer to solution 3)

(f) An angle of 135°
Since 135° = 90° + 45°
= 90° + (90/2)°
In this figure ∠ABC = 135°

Ex 14.6 Class 6 Maths Question 6.
Draw an angle of measure 45° and bisect it.

Solution:

Step I : Draw a line AB and take any point O on it.
Step II: Construct ∠AOE = 45° at O.

Step III: With centre O and proper radius, draw an arc GF.
Step IV : With centres G and F and proper radius, draw two arcs which intersect each other at D.
Step V : Join O to D.
Thus ∠AOE = 45° and OD is its bisector.

Ex 14.6 Class 6 Maths Question 7.
Draw an angle of measure 135° and bisect it.

Solution:

Steps I: Draw a line OA and take any point P on it.

Step II: Construct ∠APQ = 135°.
Step III : Draw PD as the bisector of angle APQ.

Thus ∠APQ = = 67 .

Ex 14.6 Class 6 Maths Question 8.
Draw an angle of 70°. Make a copy of it using only a straight edge and compasses.

Solution:

Step I : Draw a line AB and take any point 0 on it.
Step II : Draw ∠COB = 70° using protractor.

Step III: Draw a ray

Step IV: With centre O and proper radius, draw an arc which meets and at E and F respectively.

Step V : With the same radius and centre at P, draw an arc meeting at R.
Step VI: With centre R and keeping and radius equal to EF, draw an arc intersecting the former arc at S.
Step VII : Join P and S and produce it. Thus, QPS is the copy of AOB = 70°.

Ex 14.6 Class 6 Maths Question 9.
Draw an angle of 40°. Copy its supplementary angle.

Solution:

Step I: Construct ∠AOB = 40° using protractor.
∠COF is the supplementary angle of ∠AOB.

Step II : Draw a ray and take any point Q on it.

Step III : With centre O and proper radius, draw an arc which intersects and at E and F respectively.

Step IV : With centre Q and same radius, draw an arc which intersects at L.
Step V: With centre L and radius equal to EF, draw an arc which intersects the former arc at S.
Step VI : Join Q and S and produce.
Thus, ∠PQS is the copy of the supplementary angle COB.

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