MCQ Class 8 Maths Ganita Prakash Chapter 5 Number Play Advertisement 1. If a number is divisible by both 9 and 4, it is divisible by: 18 36 12 27Question 1 of 202. If divisible by 6 and 4, it is divisible by: 10 12 24 48Question 2 of 203. Sum of three numbers each leaving remainder 2 when divided by 6 is: Not divisible by 6 Divisible by 6 Prime OddQuestion 3 of 204. Numbers leaving remainder 2 when divided by 6 are of form: 6k 6k+2 6k–2 3kQuestion 4 of 205. Product of consecutive integers is always divisible by: 3 2 5 7Question 5 of 206. Product of 3 consecutive integers is divisible by: 2 3 6 9Question 6 of 207. Numbers divisible by 5 end with: 1 or 3 0 or 5 2 or 4 6 or 8Question 7 of 208. Digital root helps in checking divisibility by: 2 3 and 9 5 7Question 8 of 209. A number with remainder 1 when divided by 6 is of form: 6k 6k+1 6k–1 3kQuestion 9 of 2010. If sum of digits is 18, number is divisible by: 2 3 9 Both 3 and 9Question 10 of 2011. Even numbers not multiple of 4 leave remainder: 0 1 2 3Question 11 of 2012. Multiples of 4 leave remainder: 1 2 3 0Question 12 of 2013. Sum of multiple of 6 and 9 is multiple of: 2 3 6 9Question 13 of 2014. A number divisible by 8 can be written as: 2k 4k 8k 16kQuestion 14 of 2015. Remainder when 10 is divided by 9 is: 0 1 2 9Question 15 of 2016. Place values of numbers help in checking divisibility by: 2 3 9 and 11 5Question 16 of 2017. A number divisible by 11 has alternating difference: 0 or multiple of 11 Even Odd PrimeQuestion 17 of 2018. Digital root of 10 is: 0 1 2 10Question 18 of 2019. If a number is multiple of 3, its digital root is: 1 2 3,6,9 5Question 19 of 2020. Sum of digits method reduces number to: Multiple Factor Equivalent remainder PrimeQuestion 20 of 20 Loading...
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